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[SOLVED] Replacing an ampersand with &|
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ccollier
Gold member
posted
I am currently printing a report that contains the employers of people. Some employers have a '&' in their name, which ruins things. I am currently using 
 STRREP(60, EMPLOYER, 1, '&', 2, '&|', 61, EMPLOYER);
which is supposed to replace an ampersand with &|, but it still does not work. Is there any other way to do this?

This message has been edited. Last edited by: ccollier,


WebFOCUS 8.2.01M on Windows 10
 
Posts: 54 | Registered: July 30, 2018Report This Post
Waz
Expert
posted Hide Post
Try adding an extra pipe.

STRREP(60, EMPLOYER, 1, '&', 2, '&||', 61, EMPLOYER);


Waz...

Prod:WebFOCUS 7.6.10/8.1.04Upgrade:WebFOCUS 8.2.07OS:LinuxOutputs:HTML, PDF, Excel, PPT
In Focus since 1984
Pity the lost knowledge of an old programmer!

 
Posts: 6349 | Location: 33°49'23.0"S, 151°11'41.0"E | Registered: October 31, 2006Report This Post
Frans
Guru
posted Hide Post
is it being ruined with a .EVAL or something? Do you have a sample of th ecode where it breaks?


Test: WF 8.2
Prod: WF 8.2
DB: Progress, REST, IBM UniVerse/UniData, SQLServer, MySQL, PostgreSQL, Oracle, Greenplum, Athena.
 
Posts: 454 | Location: Europe | Registered: February 05, 2007Report This Post
Hallway
Master
posted Hide Post
You could try the simplified replace function as well:
  
REPLACE(EMPLOYER, '&', '&|amp;')


Hallway

 
Prod: 8202M1
Test: 8202M4
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OS:
 
Outputs:
 
 
 
 
 
Posts: 608 | Location: Salt Lake City, UT, USA | Registered: November 18, 2015Report This Post
Hallway
Master
posted Hide Post
You could also try the HEXBYT function to replace the amper
 
REPLACE(EMPLOYER, '&', HEXBYT(38, 'A1') )


Hallway

 
Prod: 8202M1
Test: 8202M4
Repository:
 
OS:
 
Outputs:
 
 
 
 
 
Posts: 608 | Location: Salt Lake City, UT, USA | Registered: November 18, 2015Report This Post
Berny
Member
posted Hide Post
I've dealt with this. Webfocus won't allow you to search for &, but you can get around that by telling it search for the &| with the | removed. Example below:

Part one - search for this character
STRIP(2, '&|', '|', 'A1')

Part Two - use replace characters searching for character in part one
REPLACE(EMPLOYER, part_one , '&||');

Full code
REPLACE(EMPLOYER, STRIP(2, '&|', '|', 'A1'), '&||');


Webfocus 8202 on Windows 10
 
Posts: 20 | Registered: February 12, 2019Report This Post
ccollier
Gold member
posted Hide Post
I used a bit of Hallway's first solution. I still used STRREP but used &|amp; instead of just &| and it worked.


WebFOCUS 8.2.01M on Windows 10
 
Posts: 54 | Registered: July 30, 2018Report This Post
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