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You can attempt using SUBSTR with the support of ARGLEN to determine how long your string actually is.
-SET &MAX_LEN = 6;
DEFINE FILE CAR
CAR_LEN/I4 = ARGLEN(20, CAR, CAR_LEN);
CAR_LAST_SIX/A6 = SUBSTR(CAR_LEN, CAR, MAX(1, CAR_LEN - &MAX_LEN + 1), CAR_LEN, MIN(CAR_LEN, &MAX_LEN), CAR_LAST_SIX);
TABLE FILE CAR
PRINT CAR AND CAR_LEN AND CAR_LAST_SIX
My sample code is a bit elaborate as I need to account for cases when the string actually has less than 6 characters. If you know for sure that your string will always have 6 or more characters, you can simplify the expression to just:
Try setting you max legth to the length of your input field and then use that in your process -SET &MAX_LEN = &INPUT.LENGTH ; DEFINE FILE CAR HOW_LONG/I5=ARGLEN (15, CAR, HOW_LONG); CAR_LAST_SIX/A&INPUT.LENGTH = SUBSTR(HOW_LONG, CAR, MAX(1, HOW_LONG - &MAX_LEN + 1), HOW_LONG, MIN(HOW_LONG, &MAX_LEN), CAR_LAST_SIX); END
WF 7.6.11 Oracle WebSphere Windows NT-5.2 x86 32bit
Try setting you max legth to the length of your input field
The purpose of &MAX_LEN in my code is not to determine the length of the field but actually the length of the substring he wants to create.
In his request, ChristianP says that he wants the last 6 characters, so instead of hard-coding it I simply set a variable with that value which can be adjusted when business rules change. Perhaps the variable name was a bit misleading so point well taken
The .LENGTH approach is only feasible when dealing with Dialogue Manager variable but not with actual fields fetched from a database table or any other source which is the assumption I made in my example.