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if that's really what your entire character string looks like, then i would use the POSIT function to determine the exact location of the . Lets say its 23,then determine the length of the whole string Lets say its 33 then 2 substring functions FRONT/A33=SUBSTR(33,input,1,23-1,23-1,'A33'); BACK/A33=SUBSTR(33,input,23+1,33,33-23,'A33') nb: SUBSTR(inlength, parent, start, end, sublength, outfield)
Hows that?
In Focus since 1979///7706m/5 ;wintel 2008/64;OAM security; Oracle db, ///MRE/BID
Posts: 3811 | Location: Manhattan | Registered: October 28, 2003
Susannah, unfortunately the array of numbers is always changing. Otherwise I think your idea would work.
Waz, I think you have exactly what I'm looking for, except I also need a variable containing the string after the '.' What is the "A&"? I am not familiar with that and I don't see anything in the help docs about it.