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Joan Williamson-Kelly
Gold member
posted
Here's a nice equivalent to Oracle
"count(distinct fieldname || fieldname)"
for when you need to know how many unique combinations of two fields are in a dataset.

It concatenates the values of the two fields in a DEFINE, then uses SUM CNT.DST to get the count of distinct combinations. Note that the result is defined as I/9, else it returns ***** as a value.


DEFINE FILE EXAMPLETABLE
CONCAT_FIELDS/A70 = FIELD1 || FIELD2;
END
TABLE FILE EXAMPLETABLE
SUM CNT.DST.CONCAT_FIELDS/I9
END

Sorry - I didn't figure this out for CAR, but am sure it could be done there. I'm putting this entry in for next time I need it and can't remember/find what I did!

Thanks to an entry in the IBI TechSupport for the basic idea, which I extended to use a concatenated DEFINE.

Cheers!
 
Posts: 64 | Location: Denver | Registered: July 20, 2005Report This Post
j.gross
Virtuoso
posted Hide Post
But use weak catenation:
CONCAT_FIELDS/A70 = FIELD1 | FIELD2;

lest rows like
field1  field2
======  ======
A       BC 
AB      C
be confounded.


- Jack Gross
WF through 8.1.05
 
Posts: 1925 | Location: NYC | In FOCUS since 1983 | Registered: January 11, 2005Report This Post
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