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I have two tables joined together as a left outer join. Table A may or may not be related to records in table B and they have a variety of relationship types. I want to show all records in table A (whether there is a relationship or not) and only those in table B where relationship type = a specific value.This message has been edited. Last edited by: <Kathryn Henning>,
There may be a 'correct' answer, but in this situation I would do 2 extracts using each set of rule and then merge the hold files together to create the whole extract. So I would do a normal join and extract the data with tablea-tableb match, then a separate left_outer join and extract the data where tableb data eq missing. Then merge the 2 hold files together with a 'table file' and 'more'.
7.7.05 Windows.
Posts: 39 | Location: UK | Registered: July 11, 2012
If you are using a LEFT_OUTER Join and have a WHERE clause with a specific value then any MISSING (ie NULL) values are automatically excluded. To bring back in those without a relationship try
WHERE B.TableB_Field EQ Spec_Value AND B.TableB_Field EQ MISSING
You may also need to add
SET ALL=PASS
depending on the adapter you are using
Cheers
Stu
WebFOCUS 8.2.03 (8.2.06 in testing)
Posts: 253 | Location: Melbourne, Australia | Registered: February 07, 2007