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How can I add 25 days to Date 1 giving me a Date 3?
Then using Date 3 determine if Date 2 is less than Date 3.
I've looked up some info on subtracting dates, but nothing has jumped out at and, and since these are alpha I wasn't sure they would work the same way.
sure look up the AYMD function. you'll need to translate these character strings into smart dates, there are many ways to do that. one way uses the date convert function DATECVT. Smart dates being the focus word for integers underlying the date formatting map, integers representing the number of days elapsed since the base date of jan1 1900. Smart dates are the way to do all the arithmetic you need. Look them both up in your FUNCTIONS manual There are a number of threads on this board about DATES. So do a board search here as well. You'll enjoy what you'll learn.
Posts: 3811 | Location: Manhattan | Registered: October 28, 2003
I have tried both of those...DATE is the name of the field that holds the date I need that is A255 but I want it to be in date format so that I can perform arithmetic.
The error tells me: (FOC36355) INVALID TYPE OF ARGUMENT #1 FOR USER FUNCTION DATECVT
But I need the first argument cause that is the date... not sure what to do. I appreciate the AYMD hint (never seen that one), I assume I will use that once I figure this first part out.
The WebFOCUS 53 "Using Functions" Document (DN4500583.0904) has the following explanation for using the DATECVT function.
DATECVT(date, 'infmt', 'outfmt'[, outfield])
WHERE infmt Alphanumeric Is the format of the date enclosed in single quotation marks. It is one of the following: * A non-legacy date format (for example, YYMD, YQ, M, DMY, JUL). * A legacy date format (for example, I6YMD or A8MDYY). * A non-date format (such as I8 or A6). A non-date format in infmt functions as an offset from the base date of a YYMD field (12/31/1900).
Going by that you should be able to use the following code to convert the date
DEFINE FILE CAR -* Using A8MDYY Format DATEA8/A8 WITH CAR = '01012005'; DTEONE/MDYY = DATECVT(DATEA8,'A8MDYY','MDYY'); -* USING A6 Format Approximately 100 years (365 * 100) from the base date of (12/31/1900) DATEA6/A6 = '36500'; DTETWO/MDYY = DATECVT(DATEA6,'A6','MDYY'); END TABLE FILE CAR PRINT DATEA8 DTEONE DATEA6 DTETWO END
Hope that helps MThis message has been edited. Last edited by: <Maryellen>,
Posts: 33 | Location: New York, USA | Registered: August 11, 2003